새로운 설정 파일을 위한 gitignore 확보
처리하지 않고 남겨둔 array 참조 해결 main.js 를 별도로 이동
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@@ -77,16 +77,16 @@ echo "
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";
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for($i=12; $i >= $lv; $i-=2) {
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$i1 = $i; $i2 = $i - 1;
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$imageTemp1 = GetImageURL($level[$i1][imgsvr]);
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$imageTemp2 = GetImageURL($level[$i2][imgsvr]);
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$imageTemp1 = GetImageURL($level[$i1]['imgsvr']);
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$imageTemp2 = GetImageURL($level[$i2]['imgsvr']);
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echo "
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<tr>
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<td width=98 align=center id=bg1><font size=4>".getLevel($i1, $nation['level'])."</font></td>
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<td width=64 height=64 background={$imageTemp1}/{$level[$i1][picture]}> </td>
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<td width=332><font size=4>";echo $level[$i1][name]==''?"-":$level[$i1][name]; echo " ({$level[$i1][belong]}년)</font></td>
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<td width=64 height=64 background={$imageTemp1}/{$level[$i1]['picture']}> </td>
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<td width=332><font size=4>";echo $level[$i1]['name']==''?"-":$level[$i1]['name']; echo " ({$level[$i1]['belong']}년)</font></td>
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<td width=98 align=center id=bg1><font size=4>".getLevel($i2, $nation['level'])."</font></td>
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<td width=64 height=64 background={$imageTemp2}/{$level[$i2][picture]}> </td>
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<td width=332><font size=4>";echo $level[$i2][name]==''?"-":$level[$i2][name]; echo " ({$level[$i2][belong]}년)</font></td>
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<td width=64 height=64 background={$imageTemp2}/{$level[$i2]['picture']}> </td>
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<td width=332><font size=4>";echo $level[$i2]['name']==''?"-":$level[$i2]['name']; echo " ({$level[$i2]['belong']}년)</font></td>
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</tr>
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";
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}
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@@ -457,13 +457,13 @@ $region = 0;
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for($j=0; $j < $citycount; $j++) {
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$city = MYDB_fetch_array($cityresult);
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$query = "select name,belong,city from general where no='$city[gen1]'";
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$query = "select name,belong,city from general where no='{$city['gen1']}'";
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$genresult = MYDB_query($query, $connect) or Error(__LINE__.MYDB_error($connect),"");
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$gen1 = MYDB_fetch_array($genresult);
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$query = "select name,belong,city from general where no='$city[gen2]'";
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$query = "select name,belong,city from general where no='{$city['gen2']}'";
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$genresult = MYDB_query($query, $connect) or Error(__LINE__.MYDB_error($connect),"");
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$gen2 = MYDB_fetch_array($genresult);
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$query = "select name,belong,city from general where no='$city[gen3]'";
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$query = "select name,belong,city from general where no='{$city['gen3']}'";
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$genresult = MYDB_query($query, $connect) or Error(__LINE__.MYDB_error($connect),"");
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$gen3 = MYDB_fetch_array($genresult);
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